Question 1

The primary winding of an electric train transformer has 400 turns and the secondary has 50.If the input voltage is 120V(rms)  what is the output voltage?

Accepted Answer

A)  15 V (rms) 
B)  30 V (rms) 
C)  60 V (rms) 
D)  2.4 V (rms) 
E)  960 V (rms) F) A) and E)
G) B) and C)

Question 2

Determine the rms voltage drop across the inductor in the circuit.

Accepted Answer

A)  11 V
B)  27.5 V
C)  33 V
D)  38.5 V
E)  30.5 VF) B) and D)
G) All of the above

Question 3

A 10.0- $\Omega$  resistor, 10.0-mH inductor, and 10.0-$\mu$F capacitor are connected in series with a 10.0-kHz voltage source.The rms current through the circuit is 0.200 A.Find the rms voltage drop across each of the 3 elements.

Accepted Answer

2.00 V, 12...

Question 4

The graphs below show the phasors  Δ\DeltaΔ Vmax and Imax for five RLC series circuits.The solid arrows represent the voltage phasors,  Δ\DeltaΔ V, and the dashed arrows represent the current phasors, Imax.The graph which represents a circuit where the capacitive reactance is greater than the inductive reactance is:

Accepted Answer

A)   
B)   
C)   
D)   
E)    F) D) and E)
G) B) and E)

Question 5

The average power input to a series alternating current circuit is minimum when:

Accepted Answer

A)  there are only a resistor and capacitor in the circuit.
B)  there are only a resistor and inductor in the circuit.
C)  there is only a resistor in the circuit.
D)  XL = XC and the circuit contains a resistor, an inductor and a capacitor.
E)  there is only a capacitor in the circuit.F) None of the above
G) B) and E)

Question 6

In a typical transmission line, the current I is very small and the voltage V is very large.A unit length of line has resistance R.For a power line that supplies power to 10 000 households, we can conclude that:

Accepted Answer

A)  IV = I2R.
B)  I = V/R.
C)  IV 
D)  IV > I2R.
E)  I2R = 0.F) C) and E)
G) All of the above

Question 7

The inductance of a tuning circuit of an AM radio is 4.00 mH.Find the capacitance of the circuit required for reception at 1200 kHz.

Accepted Answer

A)  2.10 pF
B)  4.40 pF
C)  21.2 pF
D)  43.4 pF
E)  27.6 pFF) A) and D)
G) All of the above

Question 8

For driving voltage V = Vm sin  ω \omega ω t, the current through the resistor is:

Accepted Answer

A)  Vm sin ( ω \omega ω t +  ϕ\phiϕ  ) 
B)  Vm cos ( ω \omega ω t +  ϕ\phiϕ  ) 
C)  sin ( ω \omega ω t +  ϕ\phiϕ  )  
D)  sin ( ω \omega ω t +  ϕ\phiϕ  )  
E)  sin  ω \omega ω t  F) A) and B)
G) C) and E)

Question 9

A 60.0-Hz ac generator with a peak voltage of 110 V drives a series RL circuit with R = 10.0   Ω\OmegaΩ   and L = 10.0 mH.The impedance is:

Accepted Answer

A)  3.77   Ω\OmegaΩ   .
B)  9.26   Ω\OmegaΩ   .
C)  10.0   Ω\OmegaΩ   .
D)  10.7   Ω\OmegaΩ   .
E)  13.8   Ω\OmegaΩ   . F) A) and E)
G) A) and C)

Question 10

The phase angle between V and I is:

Accepted Answer

A)   
B)   
C)   
D)   
E)   F) A) and C)
G) C) and D)

Exam 11: Alternating-Current Circuits

In a typical transmission line, the current I is very small and the voltage V is very large.A unit length of line has resistance R.For a power line that supplies power to 10 000 households, we can conclude that:

Correct Answer
verified

The phase angle between V and I is:

Correct Answer
verified

A 60.0-Hz ac generator with a peak voltage of 110 V drives a series RL circuit with R = 10.0 $\Omega$ and L = 10.0 mH.The impedance is:

Correct Answer
verified

The average power input to a series alternating current circuit is minimum when:

Correct Answer
verified

A 10.0- $\Omega$ resistor, 10.0-mH inductor, and 10.0- $\mu$ F capacitor are connected in series with a 10.0-kHz voltage source.The rms current through the circuit is 0.200 A.Find the rms voltage drop across each of the 3 elements.

Correct Answer
verified
2.00 V, 12...
View Answer

Correct Answer
verified

The inductance of a tuning circuit of an AM radio is 4.00 mH.Find the capacitance of the circuit required for reception at 1200 kHz.

Correct Answer
verified

For driving voltage V = Vm sin $\omega$ t, the current through the resistor is: $For driving voltage V = Vm sin \omega t, the current through the resistor is: A) Vm sin ( \omega t + \phi ) B) Vm cos ( \omega t + \phi ) C) sin ( \omega t + \phi ) D) sin ( \omega t + \phi ) E) sin \omega t$

Correct Answer
verified

The primary winding of an electric train transformer has 400 turns and the secondary has 50.If the input voltage is 120V(rms) what is the output voltage?

Correct Answer
verified

Determine the rms voltage drop across the inductor in the circuit.

Correct Answer
verified

Exam 11: Alternating-Current Circuits

In a typical transmission line, the current I is very small and the voltage V is very large.A unit length of line has resistance R.For a power line that supplies power to 10 000 households, we can conclude that:

Correct AnswerverifiedShow Answer

The phase angle between V and I is:

Correct AnswerverifiedShow Answer

A 60.0-Hz ac generator with a peak voltage of 110 V drives a series RL circuit with R = 10.0 Ω\OmegaΩ and L = 10.0 mH.The impedance is:

Correct AnswerverifiedShow Answer

The average power input to a series alternating current circuit is minimum when:

Correct AnswerverifiedShow Answer

A 10.0- Ω\OmegaΩ resistor, 10.0-mH inductor, and 10.0- μ\muμ F capacitor are connected in series with a 10.0-kHz voltage source.The rms current through the circuit is 0.200 A.Find the rms voltage drop across each of the 3 elements.

Correct Answerverified2.00 V, 12...View AnswerShow Answer

Correct AnswerverifiedShow Answer

The inductance of a tuning circuit of an AM radio is 4.00 mH.Find the capacitance of the circuit required for reception at 1200 kHz.

Correct AnswerverifiedShow Answer

For driving voltage V = Vm sin ω \omega ω t, the current through the resistor is:

Correct AnswerverifiedShow Answer

The primary winding of an electric train transformer has 400 turns and the secondary has 50.If the input voltage is 120V(rms) what is the output voltage?

Correct AnswerverifiedShow Answer

Determine the rms voltage drop across the inductor in the circuit.

Correct AnswerverifiedShow Answer

Correct Answer
verified

Correct Answer
verified

A 60.0-Hz ac generator with a peak voltage of 110 V drives a series RL circuit with R = 10.0 $\Omega$ and L = 10.0 mH.The impedance is:

Correct Answer
verified

Correct Answer
verified

A 10.0- $\Omega$ resistor, 10.0-mH inductor, and 10.0- $\mu$ F capacitor are connected in series with a 10.0-kHz voltage source.The rms current through the circuit is 0.200 A.Find the rms voltage drop across each of the 3 elements.

Correct Answer
verified
2.00 V, 12...
View Answer

Correct Answer
verified

Correct Answer
verified

For driving voltage V = Vm sin $\omega$ t, the current through the resistor is: $For driving voltage V = Vm sin \omega t, the current through the resistor is: A) Vm sin ( \omega t + \phi ) B) Vm cos ( \omega t + \phi ) C) sin ( \omega t + \phi ) D) sin ( \omega t + \phi ) E) sin \omega t$

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified